![]() ![]() Numbers in any row, column, or diagonal to add up to 15.ĭetermine a winning strategy for this variant? Instead of X's and O's, the numbers 1 through 9 are used. Is the one who finishes any row, column, or diagonal of all X's or Turns, and may change their mind from turn to turn. Winning strategy, a plan they can follow that guarantees that theyĮach player may put down either an X or an O on each of their Think about whether one player or another has a Here are some interesting variations of tic-tac-toe that you may To a draw (take the centre square) is easier to find. ![]() Unless your opponent is playing at random, because the only move that leads Is better if you take the corner square, but that's not necessarily true If you're the first player, you might think that your probability of winning See the images on the left for more information. ![]() If the first player selects a side square, there are several possibilities. If the first player plays first in the corner square, the second player must select the centre square. If the first player chooses the centre square to start, the second player, in order to not lose, must select one of the corner squares. This question, though: If you are the second player, what first move should you make to help ensure a draw? Play, Tic-Tac-Toe is a draw, I won't perform a detailed analysis of the best strategy for the game here. Data structures and meta-data are the key to writing generic code that doesn't repeat itself.įor example, lets say you have a list of coordinate triplets that correspond to the 8 "lines" of your tic-tac-toe board.Since everyone already knows that, with best When you have repeated code like this, think 'indirection'. This highlights why all this code duplication is error prone. There is a bug in your 3rd condition under if board = 'X'., you checking checking if board = 'X'. # checking whether the game is draw or not # checking whether current player is won or not Map(int, input("Enter row and column numbers to fix spot: ").split())) ![]() Player = 'X' if self.get_random_first_player() = 1 else 'O' This is a very cool project that uses sockets. ![]()
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